There is an array A[N] of N numbers. You have to compose an array Output[N] such that Output[i] will be equal to multiplication of all the elements of A[N] except A[i]. For example Output[0] will be multiplication of A[1] to A[N-1] and Output[1] will be multiplication of A[0] and from A[2] to A[N-1].

Solve it without division operator and in O(n).

You have 1000 integers. All are less than 1000 and greater or equal to 1. Among them, 999 are distinct and there is one that is found twice. How can you find the duplicate?

Extension to this questions is – if there are some billion numbers are there, and you have enough memory to fit all these numbers. What is the best of to do the same?

Create a function, called powerSet(), that will output the power set of the input set.

The power set in Algebra theory is the set of all subsets of a set (no..bull-set!) If a set has N elements then the power set will have 2^N elements. So if a set is denoted by {a,b} with a,bContinue reading… Create a function, called powerSet(), that will output the power set of the input set.

Difference between String str=”abc” and str=new String(”abc”)?

1) using new operator:- String st=new String(“abc”); 2) Without using new operator:- String st=”abc”; Once string object is created with or without new operator contents of string object cannot be modified. But we can modify String reference variable. when youContinue reading… Difference between String str=”abc” and str=new String(”abc”)?